因为：6x^2-7xy-3y^2+14x+y+a=(2x-3y+b)(3x+y+c)所以：(2x-3y)(3x+y)+14x+y+a=(2x-3y)(3x+y)+b(3x+y)+c(2x-3y)+bc即：：(2x-3y)(3x+y)+14x+y+a=(2x-3y)(3x+y)+(3b+2c)x+(b-3c)y+bc所以：14=3b+2c,1=b-3c,解得：b=4,c...