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1/4(4x²+2x-8)-(x²+1/2x-1)其中
1/4(4x²+2x-8)-(x²+2x-1)这道呢?
人气:133 ℃ 时间:2020-04-03 11:07:21
解答
1/4(4x²+2x-8)-(x²+1/2x-1)
=x²+ (1/2)x - 2 - x²- (1/2)x +1
=x² - x²+ (1/2)x - (1/2)x - 2+1
=-11/4(4x²+2x-8)-(x²+2x-1)这道呢?1/4(4x²+2x-8)-(x²+2x-1)=x²+ (1/2)x - 2 - x²- 2x +1=x² - x²+ (1/2)x -2x - 2+1=(-3/2)x-1
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