求极限lim(x->正无穷大)(x+sinx)/x
人气:214 ℃ 时间:2019-08-18 23:31:39
解答
lim(x->正无穷大)(x+sinx)/x
=1+lim(x->正无穷大)sinx/x
∵ -1/x正无穷大)1/x=0
∴ lim(x->正无穷大)sinx/x=0
∴ lim(x->正无穷大)(x+sinx)/x=1
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