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已知两个不同实数x、y满足x²=x+1,y²=y+1,则x的负五次方加上y负五次方的值是
人气:115 ℃ 时间:2019-10-14 04:58:01
解答
x²=x+1,x=(1±√5)/2y²=y+1,y=(1±√5)/2x≠yx+y=(1+√5)/2+(1-√5)/2=1x^5+y^5=x²*x²*x+y²*y²*y=(x+1)(x+1)*x+(y+1)(y+1)*y=x(x²+2x+1)+y(y²+2y+1)=x(x+1+2x+1)+y(y+1+2y+...
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