（x²+x）（x²+x+1）-6=0因(x²+x)²+(x²+x)-6=0(x²+x-2)(x²+x+3)=0(x-1)(x+2)(x²+x+3)=0解得x=1或x=-23（4x²-9）-2（2x-3）=03(2x+3)(2x-3)-2(2x-3)=0(2x-3)(6x+9-2)=0(...