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求双纽线r^2=4cos2θ区域的面积,用双重积分做
人气：280 ℃　时间：2020-05-08 04:38:55
解答
S=2*∫[-π/4,π/4]dθ∫[0,2√cos2θ]ρdρ
=4∫[-π/4,π/4]cos2θdθ
=2sis2θ|[-π/4,π/4]
=4
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