原式=log2[(1+√2+√3)(1+√2-√3)]
(1+√2+√3)(1+√2-√3)
=(1+√2)^2-(√3)^2
=1+2√2+2-3
=2√2
=2*2^(1/2)
=2^(3/2)
所以原式=log2[2^(3/2)]=3/2