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[x(x²y²-xy)-2y(x²-x³y)÷3x²y
人气:465 ℃ 时间:2019-11-04 11:58:44
解答
  [x(x²y²-xy)-2y(x²-x³y)]÷3x²y
 = (1/3)[(xy-1)-2(1-xy)]
 = xy-1
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