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计算:(x^2-9y^2)(x^2+3xy+9y^2)(x^2-3xy+9y^2)
人气:286 ℃ 时间:2020-01-28 18:10:22
解答
(x^2-9y^2)(x^2+3xy+9y^2)(x^2-3xy+9y^2)
=(x+3y)(x-3y)(x^2+3xy+9y^2)(x^2-3xy+9y^2)
=[(x+3y)(x^2-3xy+9y^2)][(x-3y)(x^2+3xy+9y^2)]
=(x^3+27y^3)(x^3-27y^3)
=x^6-729y^6
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