若f(x)=x^2-x+b,且f(log2(a))=b,log2[f(a)]=2(a不等于1),求f(log2(x))的最小值
人气:344 ℃ 时间:2019-10-08 11:45:30
解答
∵抛物线y = f(x)的对称轴为直线 x - 1/2 = 0 f[log2(a)]=b 言下之意log2(a)=0 或 1∴a =2a = 1 (舍去)因此,根据log2[f(a)] =2可知: b = 2设log2(x) = t则:x = 2^t∴f(t ) = (2^t)&...
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