1）f(x)=x²-x+b ,且 f(log2 a)=b那么 (log2a)²-log2 a+b=blog2 a (log2 a-1)=0因为 a不等于1 所以 log2 a不等于0 则 log2 a=1所以,a=2f(2)=2+b log2 (f(a))=log2(f(2))=log2 (2+b)=2因此,2²=2+b b =2...