f(x)=2sin(ωx+θ)+2cos^2(ωx+θ)-1
=2sin(ωx+θ)+2[1-sin^2(ωx+θ)]-1
=2sin(ωx+θ)-2sin^2(ωx+θ)+1
1. 由于f(x)的周期是π,2π/ω=π,ω=2.
2.由于f(x)是偶函数,所以sin(ωx+θ）为偶函数,所以θ=π/2.