(1)∵f(x)=2cos²wx+2sinwxcoswx+1=(2cos²wx-1)+2sinwxcoswx+2=cos2wx+sin2wx+2=√2sin(2wx+π/4)+2∵-1≤sin(2wx+π/4)≤1,∴2-2√2≤f(x)≤2√2+2(2)∵f(x)的最小正周期是π/2∴2π/2w=π/2,解得w=2∴f(x...