由题设易知,ax²-bx+c=a(x+2)(x-3)=ax²-ax-6a∴b=a,c=-6a.a＜0.∴不等式cx²+bx+a＞0即是：-6ax²+ax+a＞0.===>6x²-x-1＞0.===>[x-(1/2)][x+(1/3)]＞0.===>x＜-1/3,或x＞1/2.∴解集为(-∞,-1/...