> 数学 >
数学证明恒等式
sin(a+b)cos(a-b)=sinacosa+sinbcosb
人气:212 ℃ 时间:2020-05-08 02:34:09
解答
sin(a+b)cos(a-b)
=(sinacosb+cosasinb)(cosacosb+sinasinb)
=sinacosa(cosb)^2+(sina)^2sinbcosb+(cosa)^2sinbcosb+(sinb)^2sinacosa
=sinacosa[(cosb)^2+(sinb)^2]+sinbcosb[(sina)^2+(cosa)^2]
=sinacosa*1+sinbcosb*1
=sinacosa+sinbcosb
推荐
猜你喜欢
© 2024 79432.Com All Rights Reserved.
电脑版|手机版