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化简:sin(3丌-a)/tan(a-5丌)x tan(-a+2丌)/cot(丌-a)x cos(4丌-a)/sin(-a-2丌)
人气:292 ℃ 时间:2020-04-16 20:37:59
解答
sin(3丌-a)/tan(a-5丌)x tan(-a+2丌)/cot(丌-a)x cos(4丌-a)/sin(-a-2丌)
= sin(丌-a)/tan(a-丌)x tan(-a)/cot(丌-a)x cos(-a)/sin(-a)
= sina/tana x (- tana)/cota xcosa/(-sina)
= sina/tana x tana/cota xcosa/sina
= sina/tana x tana/cota xcota
= sina
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