2x+3y-z=4,3x-2y+3z=7,x+3y-2z=-1
解三元一次方程组
2x+3y-z=4
3x-2y+3z=7
x+3y-2z=-1
人气:425 ℃ 时间:2020-03-16 05:07:10
解答
2x+3y-z=4 (1)
3x-2y+3z=7 (2)
x+3y-2z=-1 (3)
(1)×2+(2)×3
13x+7z=29 (4)
(1)-(3)
x+z=5 (5)
(4)-(5)×7
13x-7x=29-35
6x=-6
所以
x=-1
z=5-x=6
y=(3x+3z-7)/2=4
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