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如图直线ab与cd相交于点o,od平分∠boe,∠aoe:∠eob=5:4求∠aoc
人气:316 ℃ 时间:2020-03-29 03:47:54
解答
∵∠aoe:∠eob=5:4
∴∠eob=4/9×180
=80°
∠aoe=5/9×180
=100°
又∵od平分∠boe
∴∠doe=1/2∠boe
=1/2×80
=40°
∴∠aoc=∠cod-∠aoe-∠doe
=180-100-40
=40°
答:∠aoc的度数为40°.
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