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证明:(cos3θ+sin3θ)/(cosθ-sinθ) =1+2sin2θ
人气:116 ℃ 时间:2020-05-27 09:41:26
解答
(cos3θ+sin3θ)/(cosθ-sinθ)
=(4cos³θ-3cosθ+3sinθ-4sin³θ)/(cosθ-sinθ)
=[4(cos³θ-sin³θ)-3(cosθ-sinθ)]/(cosθ-sinθ)
=4(cos²θ+cosθsinθ+sin²θ)-3
=4(1+0.5sin2θ)-3
=1+2sin2θ
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