(wx+π/3)-(wx-π/6)=π/2 ==>(wx+π/3)=π/2+(wx-π/6) 两边取正弦得：sin(wx+π/3)=sin[π/2+(wx-π/6)]=cos(wx-π/6)f(x)=1/2sin(2wx-π/3)因为相邻两条对称轴之间的距离为π/2即：T/2=π/2 ==>T=π=2π/2w ==>w=...