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s/(2s/3v1+s/3v2)=化简过程
人气:266 ℃ 时间:2020-04-30 01:22:07
解答
s/(2s/3v1+s/3v2)
=1/(2/3v1+1/3v2)
=(3v1v2)/(2v2+v1)
=3v1v2/(v1+2v2)
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