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已知函数f(x)=根号(sin(x/2)^4+4cos(x/2)^2)-根号(cos(x/2)^4+4sin(x/2)^2)
(1)化简f(x),并求f(25π/6)
(2)若0<α<π,f(α)+f(α/2)=0,求α
(要过程啊~)
人气:144 ℃ 时间:2019-10-11 20:29:35
解答
解1:f(x)=√[sin(x/2)^4+4cos(x/2)^2]-√[cos(x/2)^4+4sin(x/2)^2]=√{[1-cos(x/2)^2]^2+4cos(x/2)^2}-√{[1-sin(x/2)^2]^2+4sin(x/2)^2}=√[1+2cos(x/2)^2+cos(x/2)^4]-√[1-2sin(x/2)^2+sin(x/2)^4+4sin(x/2)^2]=...
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