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当-π/2≤x≤π/2,函数f(X)=2sin(x+π/3)最大值是?最小值?
人气:454 ℃ 时间:2019-11-09 14:42:19
解答
-π/2 ≤ x ≤ π/2
-π/2 +π/3 ≤ x +π/3 ≤ π/2 + π/3
-π/6 ≤ x +π/3 ≤ 5π/6
-1/2 ≤ sin(x +π/3) ≤ 1
-1 ≤ 2sin(x +π/3) ≤ 2
-1 ≤ f(x) ≤ 2
所以
最大值是 2
最小值是 -1
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