2x+√(2x-3)-5=0
2x-3+√(2x-3)-2=0
设y＝√2x-3
y^2+y-2=0
(y+2)(y-1)=0
y1=-2 (舍去) y2=1
√(2x-3)=1
2x-3=1
2x=4
x=2