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根号27+(2-根号6)/根号3-(兀-3)^0
人气:189 ℃ 时间:2020-06-21 08:15:33
解答
根号27+(2-根号6)/根号3-(兀-3)^0
=3√3+(2-√6)√3/3 - 1
=3√3+ 2√3/3-√2 - 1
=11√3/3 -√2 - 1
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