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数学
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计算:(1/4a^2b)×(-2ab^2)÷(0.5a^4b^5)
人气:428 ℃ 时间:2020-03-27 10:30:32
解答
(1/4a^2b)×(-2ab^2)÷(0.5a^4b^5)
=[(1/4)(-2)/0.5][(a^2)ba(b^2)]/[(a^4)(b^5)]
=-[(a^3)(b^3)]/[(a^4)(b^5)]
=-1/(ab^2)
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