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Sina^4+2√3sinacosa-cos^4
化简
人气:132 ℃ 时间:2020-06-09 10:23:14
解答
Sina^4+2√3sinacosa-cosa^4
=√3sin2a+(sina^2+cos^2)(sina^2-cosa^2)
=√3sin2a+sina^2-cosa^2
=√3sin2a-(cosa^2-sina^2)
=2(√3/2sin2a-1/2cos2a)
=2(sin2acosπ/6-cos2asinπ/6)
=2sin(2a-π/6)
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