若丨x-3丨+(x-y+1)^2=0,计算根号X^2Y + XY^2 +4分之y^3=根号X2Y + XY2 +Y2_数学解答

若丨x-3丨+(x-y+1)^2=0,计算根号X^2Y + XY^2 +4分之y^3=
根号X2Y + XY2 +Y2

人气：282 ℃　时间：2020-05-11 16:42:45

解答

丨x-3丨+(x-y+1)^2=0
则x=3,y=4
所以x^2y+xy^2+y^3/4
=3^2*4+3*4^2+4^3/4
=36+48+16
=84+16
=100