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a,b均为质数,且3a+4b=41,则a+b是多少?
人气:221 ℃ 时间:2020-09-16 06:50:24
解答
a = 7 ,b = 5 ,a + b = 12
a = 11 ,b = 2 ,a + b = 13还可以,不过不完整a = (41 - 4b)/3 = 14 - b - (1 + b)/3b = (41 - 3a) /4 < 111 + b 为 3的倍数,且为小于 11 的质数:b 只能是 2、5所以:a = 7 , b = 5 , a + b = 12a = 11 , b = 2 , a + b = 13
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