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函数f(x)=a的x次方+log以a为底(x+1)在【0,1】上的最大值和最小值德赫为a,则a的值为?
人气:485 ℃ 时间:2020-03-18 14:26:55
解答
当a>1时,f(x)在[0,1]上单调递增f(x)max=f(1)=a+log(a)2f(x)min=f(0)=1a+log(a)2+1=a解得:a=1/2<1,舍去当0<a<1时,f(x)在[0,1]上单调递减f(x)min=f(1)=a+log(a)2f(x)max=f(0)=1a+log(a)2+1=a解得:a=1/2...
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