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(3)(m的平方-9分之12)+(3-m分之2)+(m+3分之2)
人气:272 ℃ 时间:2020-05-21 20:18:09
解答
12/(m^2-9)+2/(3-m)+2/(m+3)
=12/(m^2-9)-2/(m-3)+2/(m+3)
=12/[(m-3)(m+3)]-2(m+3)/[(m-3)(m+3)]+2(m-3)/[(m-3)(m+3)]
=[12-2(m+3)+2(m-3)]/[(m-3)(m+3)]
=[12-2m-6+2m-6]/[(m-3)(m+3)]
=0/[(m-3)(m+3)]
=0
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