x^2 y^2=e^xy隐函数求导
人气:430 ℃ 时间:2020-03-25 04:33:03
解答
x(y^2)- e^xy + 2 = 0\r\n\r\n两端同时求导:\r\n(y^2 + 2xy'y) - e^xy(y+xy') = 0\r\n集项:\r\n(2xy - xe^xy)y' = (ye^xy - y^2)\r\n则:\r\ndy\/dx = y' = (ye^xy - y^2)\/(2xy - xe^xy)
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