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隐函数求导 x+y-e^xy=0
其实他让求的是dy/dx
人气:240 ℃ 时间:2020-03-25 10:49:02
解答
dx/dx+dy/dx-e^(xy)(y+x*dy/dx)=0
=>dy/dx*(1-xe^(xy))=-1+y*e^(xy)
=>dy/dx=[-1+y*e^(xy)]/[1-xe^(xy)]=(xy+yy-1)/(1-xx-xy)
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