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(-1又5分之2)2
-(-0.1)3
-丨-7分之2丨2
-3(3)÷(-3)2
-3分之1×(-3)3
(-2)2·(-3)2
-(-3)2×(-2)3
6×(-2)2÷(-2(3))
-2(3)÷9分之4×(-3分之2)×(-2)3分之1
人气:438 ℃ 时间:2020-09-05 13:59:25
解答
(-1又5分之2)2
=(-7/5)^2
=49/25
-(-0.1)3
=(0.1)^3
=0.001
-丨-7分之2丨2
=-(2/7)^2=-4/49
-3(3)÷(-3)2
=-9/9=-1
-3分之1×(-3)3
=(1/3)*27=9
(-2)2·(-3)2
=4*9=36
-(-3)2×(-2)3
=-9*(-8)=9*8=72
6×(-2)2÷(-2(3))
=6*4/(-6)=-4
-2(3)÷9分之4×(-3分之2)×(-2)3分之1
=-6*9/4*(-2/3)*(-2/3)=-6
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