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数学
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证明:tanx sinx / (tanx -sinx)=(tanx+sinx) / tanx sinx
人气:249 ℃ 时间:2020-01-30 15:01:20
解答
左边=sinx/cosx*sinx/(sinx/cosx-sinx)
上下乘cosx
=sin²x/(sinx-sinxcosx)
=sinx/(1-cosx)
上下乘1+cosx
=(sinx+sinxcosx)/(1-cos²x)
=(sinx+sinxcosx)/sin²x
上下除以cosx
=(sinx/cosx+sinx)/(sinx/cosx*sinx)
=(tanx+sinx) / tanx sinx
=右边
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