> 数学 >
初一因式分解2道
x^2-xy-2y^2-3x+2
x^3+x^2-4x+2
人气:259 ℃ 时间:2020-06-02 22:57:54
解答
=x²-2xy-2x+xy-2y²-2y-x+2y+2=x(x-2y-2)+y(x-2y-2)-(x-2y-2)=(x-2y-2)(x+y-1)=x³-x²+2x²-2x-2x+2=x²(x-1)+2x(x-1)-2(x-1)=(x-1)(x²+2x-2)
推荐
猜你喜欢
© 2024 79432.Com All Rights Reserved.
电脑版|手机版