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已知tan(a+π/4)=2,则1+sinacosa-2(cosa)^2
人气:448 ℃ 时间:2020-10-01 22:46:03
解答
tan(a+π/4)=2tan(a+π/4-π/4)= [tan(a+π/4)-tan(π/4)]/[1+tan(a+π/4)tan(π/4)]=(2-1)/3=1/3所以sina/cosa=1/3cosa=3sinacos²a+sin²a=110sin²a=1 sin²a=1/10,cos²a=9/10sina co...
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