[(x+2)/(x-1)]*[(x^2-2x+1)/(x^2-x-6)]-(2x-6)/(x^2-9)
=[(x+2)/(x-1)]*[(x-1)^2/(x-3)(x+2)]-2(x-3)/(x+3)(x-3)
=(x+2)(x-1)^2/[(x-1)(x-3)(x+2)]-2/(x+3)
=(x-1)/(x-3)-2/(x+3)
=[(x-1)(x+3)-2(x-3)]/(x+3)(x-3)
=(x^2+2x-3-2x+6)/(x+3)(x-3)
=(x^2+3)/(x+3)(x-3)
(x^2-1)/(x-1)+x(1+1/x)
=(x+1)(x-1)/(x-1)+x+1
=x+1+x+1
=2x+2
=2根号2-2+2
=2根号2