计算 2xy[4x²y²-3y(xy+x²y)-xy²]
(2x-x²-3)(x³-x²-2)
(x²)³-2x³[x³-x²(4x+1)]
(-1/3xy)²·[xy(2x-y)-3x(xy-y²)]
人气:396 ℃ 时间:2019-09-17 04:47:19
解答
2xy [4x²y²-3y(xy+x²y)-xy²]= 2xy [4x²y²-3xy²-3x²y²-xy²]= 2xy [x²y²-4xy²]= 2x³y³-8x²y³(2x-x²-3)(x³-x...
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