已知全集I={0,1,2},且满足CI(A∪B)={2}的A、B共有组数( )
A. 5
B. 7
C. 9
D. 11
人气:186 ℃ 时间:2020-05-31 18:18:00
解答
∵全集I={0,1,2},且满足CI(A∪B)={2},∴A∪B={ 0,1}.
当A=∅时,仅有一个B={0,1 }.
当A={0}时,B有2个,B={0,1 },或B={1 }.
当A={1}时,B有2个,B={0,1 },或B={0 }.
当A={0,1}时,B有4个,B={0,1 },或B={0 },或B={1 },或B=∅.
综上可得,满足CI(A∪B)={2}的A、B共有组数为9,
故选C.
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