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数学
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{2s=3t ① {s=(2t+5)/3 ②
用代数消元法解二元一次方程组!
人气:365 ℃ 时间:2020-04-19 19:02:00
解答
解
将②代入①得;
2(2t+5)/3=3t
即2(2t+5)=9t
即4t+10=9t
∴5t=10
∴t=2
将t=2代入①得:2s=3×2=6
∴s=3
∴s=3,t=2
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