y=(sin^2x)/sin(x^2)的详细求导过程._数学解答

y=(sin^2x)/sin(x^2)的详细求导过程.

人气：112 ℃　时间：2020-04-13 09:33:56

解答

y=(sin^2x)/sin(x^2)y'={(sin^2x)'sin(x^2)-(sin^2x)[sin(x^2)]'}/sin^2(x^2)={(2sinxcosx)sin(x^2)-(sin^2x)[2xcos(x^2)]}/sin^2(x^2)=[sin2xsin(x^2)-2xsin^2xcos(x^2)]/sin^2(x^2).