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已知m=99又1/2,n=50又1/4,求代数式(2m-n)^2-(3m-n)(m-n)-4n^2的值
人气:172 ℃ 时间:2019-11-22 22:22:51
解答

(2m-n)^2-(3m-n)(m-n)-4n^2
=(4m^2-4mn+n^2)-(3m^2-4mn+n^2)-4n^2
=4m^2-4mn+n^2-3m^2+4mn-n^2-4n^2
=m^2-4n^2
=(m+2n)(m-2n)
=200*(-4)
=-800
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