设正反比例函数分别为y=k1xy=k2/x因点(-2,1)在图像上则有1=-2k1所以 k1 = -1/2则函数解析式为y = (-1/2)x同理1=k2/-2所以 k2 = -2则函数解析式为y = -2/x联立两方程得y = (-1/2)xy = -2/x解得x1=-2y1=1x2=2y2=-1则另...