计算①x²-4／x²-4x+3÷x²+3x+2／x²-x②2x+6／4-4x+x²÷(x+3)·x²+x-6／3-x
人气：421 ℃ 时间：2020-01-27 15:32:19
解答
①x²-4／x²-4x+3÷x²+3x+2／x²-x=(x²-4)/(x²-4x+3)÷(x²+3x+2)/(x²-x)=(x-2)(x+2)/(x-1)(x-3)÷(x+1)(x+2)/x(x-1)=x(x-2)(x+2)(x-1)/[(x-1)(x-3)(x+1)(x+2)]=(x²-2x)/...
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