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数学
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∫dx/根号2x+1的不定积分
人气：235 ℃ 时间：2020-04-11 21:28:15
解答
t=根号（2x+1),x=1/2*t^2-1/2 dx=tdt
∫dx/根号2x+1dx
=S1/t *tdt
=Sdt
=t+c
=根号(2x+1)+c
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