(x-2)²+∣y-3∣=0
(x-2)²=0,∣y-3∣=0
x=2
y=3
(x-y)/(x²-2xy+y²)-(xy+y²)/(x²-y²)
=(x-y)/(x-y)²-y(x+y)/(x-y)(x+y)
=1/(x-y)-y/(x-y)
=(1-y)/(x-y)
=(1-3)/(2-3)
=-2/(-1)
=2