证明两个连续奇数的平方差能被8整除.
人气:421 ℃ 时间:2019-10-24 07:20:31
解答
设两个连续奇数为2n-1,2n+1,
则(2n+1)2-(2n-1)2=(2n+1+2n-1)(2n+1-2n+1)=8n,
故能被8整除.
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