用dy/dx的形式求导数y=a^x
人气:400 ℃ 时间:2019-12-01 07:19:02
解答
y' = lim(t->0)(a^(x+t)-a^x)/t
= a^x * lim(t->0)(a^t-1)/t
= a^x * lna * lim(t->0)(e^(t*lna)-1)/t*lna
根据等价无穷小,后面的lim等于1
所以y'=a^x * lna
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