f(x)=2x^3-3x^2+ax+b
=2x^3+2x^2-5x^2+ax+b
=2x^2*(x+1)-5x^2-5x+5x+ax+b
=2x^2*(x+1)-5x(x+1)+(a+5)x+(a+5)-a-5+b
=2x^2*(x+1)-5x(x+1)+(a+5)(x+1)+(b-a-5)
所以：b-a-5=7 --------------（1）
f(x)=2x^3-3x^2+ax+b
=2x^3-2x^2-x^2+ax+b
=2x^2*(x-1)-x^2+x+(a-1)x+b
=2x^2*(x-1)-x(x-1)+(a-1)(x-1)+(b+a-1)
所以：a+b-1=5 -------------- (2)
联立（1）,（2）得：
a=-3,b=9